(Q34)It is given that in a group of 3 students, the probability of 2 students not having the same birthday is 0.992.What is the probability that the 2 students have the same birthday?

Answer :

Let P(E) = The probability that two students not having the same birthday = 0.992

Then P(Ē) = The complementary event of E, i.e., two students having the same birthday Also, P(E) + p(Ē) =

∴ The probability that two students have the same birthday P(Ē) = - P(E)

= - 0.992 =